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131403010202341 is a prime number
BaseRepresentation
bin11101111000001010100101…
…101111101101101011100101
3122020021000010201020012120021
4131320022211233231223211
5114210401331102433331
61143245413131435141
736451361042515603
oct3570124557555345
9566230121205507
10131403010202341
1138961781654049
12128a294a2b5ab1
135842334a06277
142463d224a8873
15102d161b15211
hex7782a5bedae5

131403010202341 has 2 divisors, whose sum is σ = 131403010202342. Its totient is φ = 131403010202340.

The previous prime is 131403010202311. The next prime is 131403010202357. The reversal of 131403010202341 is 143202010304131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131231825277316 + 171184925025 = 11455646^2 + 413745^2 .

It is a cyclic number.

It is not a de Polignac number, because 131403010202341 - 227 = 131402875984613 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131403010202311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701505101170 + 65701505101171.

It is an arithmetic number, because the mean of its divisors is an integer number (65701505101171).

Almost surely, 2131403010202341 is an apocalyptic number.

It is an amenable number.

131403010202341 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403010202341 is an equidigital number, since it uses as much as digits as its factorization.

131403010202341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 131403010202341 its reverse (143202010304131), we get a palindrome (274605020506472).

The spelling of 131403010202341 in words is "one hundred thirty-one trillion, four hundred three billion, ten million, two hundred two thousand, three hundred forty-one".