Base | Representation |
---|---|
bin | 11000011110011100… |
… | …10010001000100101 |
3 | 1020220202210121221112 |
4 | 30033032102020211 |
5 | 203402404220141 |
6 | 10011522154405 |
7 | 643425513266 |
oct | 141716221045 |
9 | 36822717845 |
10 | 13140304421 |
11 | 56333a5222 |
12 | 26687b2a05 |
13 | 131548777a |
14 | 8c924c96d |
15 | 51d9187eb |
hex | 30f392225 |
13140304421 has 2 divisors, whose sum is σ = 13140304422. Its totient is φ = 13140304420.
The previous prime is 13140304403. The next prime is 13140304423. The reversal of 13140304421 is 12440304131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9763416100 + 3376888321 = 98810^2 + 58111^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13140304421 is a prime.
It is a Sophie Germain prime.
Together with 13140304423, it forms a pair of twin primes.
It is a Chen prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13140304423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570152210 + 6570152211.
It is an arithmetic number, because the mean of its divisors is an integer number (6570152211).
Almost surely, 213140304421 is an apocalyptic number.
It is an amenable number.
13140304421 is a deficient number, since it is larger than the sum of its proper divisors (1).
13140304421 is an equidigital number, since it uses as much as digits as its factorization.
13140304421 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13140304421 its reverse (12440304131), we get a palindrome (25580608552).
The spelling of 13140304421 in words is "thirteen billion, one hundred forty million, three hundred four thousand, four hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.113 sec. • engine limits •