Base | Representation |
---|---|
bin | 1011111100110111011110… |
… | …0110000001000100111010 |
3 | 1201112012102220011211102100 |
4 | 2333031313212001010322 |
5 | 3210242324210204200 |
6 | 43540324205044230 |
7 | 2524233111053433 |
oct | 277156746010472 |
9 | 51465386154370 |
10 | 13140311413050 |
11 | 4206858253098 |
12 | 158281b856676 |
13 | 744183c12c93 |
14 | 335dccb5848a |
15 | 17bc228bdd00 |
hex | bf37798113a |
13140311413050 has 72 divisors (see below), whose sum is σ = 35311573664640. Its totient is φ = 3503295252000.
The previous prime is 13140311413043. The next prime is 13140311413171. The reversal of 13140311413050 is 5031411304131.
13140311413050 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 0 + 311 + 41 + 305 + 0 = 666.
It is an unprimeable number.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 1277290 + ... + 5283189.
It is an arithmetic number, because the mean of its divisors is an integer number (490438523120).
Almost surely, 213140311413050 is an apocalyptic number.
13140311413050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13140311413050 is an abundant number, since it is smaller than the sum of its proper divisors (22171262251590).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13140311413050 is a wasteful number, since it uses less digits than its factorization.
13140311413050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6564948 (or 6564940 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 27.
Adding to 13140311413050 its reverse (5031411304131), we get a palindrome (18171722717181).
The spelling of 13140311413050 in words is "thirteen trillion, one hundred forty billion, three hundred eleven million, four hundred thirteen thousand, fifty".
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