Base | Representation |
---|---|
bin | 1011111100110111011110… |
… | …1101111111010110001010 |
3 | 1201112012110001010000110010 |
4 | 2333031313231333112022 |
5 | 3210242330224044424 |
6 | 43540324321532350 |
7 | 2524233134610060 |
oct | 277156755772612 |
9 | 51465401100403 |
10 | 13140313503114 |
11 | 4206859450416 |
12 | 15828204a40b6 |
13 | 7441844953c5 |
14 | 335dcd140030 |
15 | 17bc22b83229 |
hex | bf377b7f58a |
13140313503114 has 64 divisors (see below), whose sum is σ = 30400481341440. Its totient is φ = 3708701156160.
The previous prime is 13140313503103. The next prime is 13140313503137. The reversal of 13140313503114 is 41130531304131.
It is a super-3 number, since 3×131403135031143 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 29693727 + ... + 30133005.
It is an arithmetic number, because the mean of its divisors is an integer number (475007520960).
Almost surely, 213140313503114 is an apocalyptic number.
13140313503114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13140313503114 is an abundant number, since it is smaller than the sum of its proper divisors (17260167838326).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13140313503114 is a wasteful number, since it uses less digits than its factorization.
13140313503114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 447955.
The product of its (nonzero) digits is 6480, while the sum is 30.
Adding to 13140313503114 its reverse (41130531304131), we get a palindrome (54270844807245).
The spelling of 13140313503114 in words is "thirteen trillion, one hundred forty billion, three hundred thirteen million, five hundred three thousand, one hundred fourteen".
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