Base | Representation |
---|---|
bin | 1011111100110111100011… |
… | …1000110100111110010011 |
3 | 1201112012111102000201201022 |
4 | 2333031320320310332103 |
5 | 3210242400234341202 |
6 | 43540330302230055 |
7 | 2524233463426241 |
oct | 277157070647623 |
9 | 51465442021638 |
10 | 13140333121427 |
11 | 420686952a9a6 |
12 | 1582826b8532b |
13 | 744188573b85 |
14 | 335dd19a9791 |
15 | 17bc2475aea2 |
hex | bf378e34f93 |
13140333121427 has 2 divisors, whose sum is σ = 13140333121428. Its totient is φ = 13140333121426.
The previous prime is 13140333121397. The next prime is 13140333121457. The reversal of 13140333121427 is 72412133304131.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (13140333121397) and next prime (13140333121457).
It is a cyclic number.
It is not a de Polignac number, because 13140333121427 - 210 = 13140333120403 is a prime.
It is not a weakly prime, because it can be changed into another prime (13140333121457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570166560713 + 6570166560714.
It is an arithmetic number, because the mean of its divisors is an integer number (6570166560714).
Almost surely, 213140333121427 is an apocalyptic number.
13140333121427 is a deficient number, since it is larger than the sum of its proper divisors (1).
13140333121427 is an equidigital number, since it uses as much as digits as its factorization.
13140333121427 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36288, while the sum is 35.
Adding to 13140333121427 its reverse (72412133304131), we get a palindrome (85552466425558).
The spelling of 13140333121427 in words is "thirteen trillion, one hundred forty billion, three hundred thirty-three million, one hundred twenty-one thousand, four hundred twenty-seven".
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