Base | Representation |
---|---|
bin | 10011000111110010100… |
… | …010010111011101100110 |
3 | 11122121202022000122101202 |
4 | 103013302202113131212 |
5 | 133012120213324200 |
6 | 2443354155322502 |
7 | 163635663506624 |
oct | 23076242273546 |
9 | 4577668018352 |
10 | 1314034120550 |
11 | 467308005728 |
12 | 192803450432 |
13 | 96bb37c1998 |
14 | 478573c4514 |
15 | 242ab0481d5 |
hex | 131f2897766 |
1314034120550 has 12 divisors (see below), whose sum is σ = 2444103464316. Its totient is φ = 525613648200.
The previous prime is 1314034120549. The next prime is 1314034120561. The reversal of 1314034120550 is 550214304131.
It is a super-2 number, since 2×13140341205502 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 13140341156 + ... + 13140341255.
It is an arithmetic number, because the mean of its divisors is an integer number (203675288693).
Almost surely, 21314034120550 is an apocalyptic number.
1314034120550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1314034120550 is a deficient number, since it is larger than the sum of its proper divisors (1130069343766).
1314034120550 is a wasteful number, since it uses less digits than its factorization.
1314034120550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26280682423 (or 26280682418 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 1314034120550 its reverse (550214304131), we get a palindrome (1864248424681).
The spelling of 1314034120550 in words is "one trillion, three hundred fourteen billion, thirty-four million, one hundred twenty thousand, five hundred fifty".
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