Base | Representation |
---|---|
bin | 10011000111110010100… |
… | …010101011110000001101 |
3 | 11122121202022011212101221 |
4 | 103013302202223300031 |
5 | 133012120224004121 |
6 | 2443354201203341 |
7 | 163635664304134 |
oct | 23076242536015 |
9 | 4577668155357 |
10 | 1314034203661 |
11 | 467308062113 |
12 | 192803490551 |
13 | 96bb382076a |
14 | 4785740691b |
15 | 242ab062b41 |
hex | 131f28abc0d |
1314034203661 has 2 divisors, whose sum is σ = 1314034203662. Its totient is φ = 1314034203660.
The previous prime is 1314034203577. The next prime is 1314034203673. The reversal of 1314034203661 is 1663024304131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1204135323561 + 109898880100 = 1097331^2 + 331510^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1314034203661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314034203961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657017101830 + 657017101831.
It is an arithmetic number, because the mean of its divisors is an integer number (657017101831).
Almost surely, 21314034203661 is an apocalyptic number.
It is an amenable number.
1314034203661 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314034203661 is an equidigital number, since it uses as much as digits as its factorization.
1314034203661 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 34.
Adding to 1314034203661 its reverse (1663024304131), we get a palindrome (2977058507792).
The spelling of 1314034203661 in words is "one trillion, three hundred fourteen billion, thirty-four million, two hundred three thousand, six hundred sixty-one".
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