Base | Representation |
---|---|
bin | 11101111000001010111110… |
… | …110001001010011010000000 |
3 | 122020021001012222011202220022 |
4 | 131320022332301022122000 |
5 | 114210403211040400134 |
6 | 1143245522525433012 |
7 | 36451404331036214 |
oct | 3570127661123200 |
9 | 566231188152808 |
10 | 131403430012544 |
11 | 3896197761a728 |
12 | 128a2a46a0b768 |
13 | 58423a0992781 |
14 | 2463d62148944 |
15 | 102d1888dd52e |
hex | 7782bec4a680 |
131403430012544 has 32 divisors (see below), whose sum is σ = 262875585729600. Its totient is φ = 65426812417792.
The previous prime is 131403430012447. The next prime is 131403430012571. The reversal of 131403430012544 is 445210034304131.
It is a tau number, because it is divible by the number of its divisors (32).
It is a super-2 number, since 2×1314034300125442 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2147645762 + ... + 2147706945.
It is an arithmetic number, because the mean of its divisors is an integer number (8214862054050).
Almost surely, 2131403430012544 is an apocalyptic number.
It is an amenable number.
131403430012544 is an abundant number, since it is smaller than the sum of its proper divisors (131472155717056).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131403430012544 is an equidigital number, since it uses as much as digits as its factorization.
131403430012544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4295352960 (or 4295352948 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 131403430012544 its reverse (445210034304131), we get a palindrome (576613464316675).
The spelling of 131403430012544 in words is "one hundred thirty-one trillion, four hundred three billion, four hundred thirty million, twelve thousand, five hundred forty-four".
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