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131403434117 is a prime number
BaseRepresentation
bin111101001100001000…
…0010100100010000101
3110120011201202002022012
41322120100110202011
54123103234342432
6140211011344005
712331204522004
oct1723020244205
9416151662265
10131403434117
11508008a3a3a
12215728b2005
13c511886417
146507a32c3b
153641185cb2
hex1e98414885

131403434117 has 2 divisors, whose sum is σ = 131403434118. Its totient is φ = 131403434116.

The previous prime is 131403434083. The next prime is 131403434143. The reversal of 131403434117 is 711434304131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121069898401 + 10333535716 = 347951^2 + 101654^2 .

It is a cyclic number.

It is not a de Polignac number, because 131403434117 - 210 = 131403433093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131403434417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701717058 + 65701717059.

It is an arithmetic number, because the mean of its divisors is an integer number (65701717059).

Almost surely, 2131403434117 is an apocalyptic number.

It is an amenable number.

131403434117 is a deficient number, since it is larger than the sum of its proper divisors (1).

131403434117 is an equidigital number, since it uses as much as digits as its factorization.

131403434117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 32.

Adding to 131403434117 its reverse (711434304131), we get a palindrome (842837738248).

The spelling of 131403434117 in words is "one hundred thirty-one billion, four hundred three million, four hundred thirty-four thousand, one hundred seventeen".