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13140345313541 is a prime number
BaseRepresentation
bin1011111100110111100110…
…0111010101100100000101
31201112012112020222011011002
42333031321213111210011
53210242411400013131
643540331415423045
72524234002155615
oct277157147254405
951465466864132
1013140345313541
1142068753a8026
12158282b084a85
1374418ac52444
14335dd3460a45
1517bc258686cb
hexbf3799d5905

13140345313541 has 2 divisors, whose sum is σ = 13140345313542. Its totient is φ = 13140345313540.

The previous prime is 13140345313489. The next prime is 13140345313549. The reversal of 13140345313541 is 14531354304131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7542460293316 + 5597885020225 = 2746354^2 + 2365985^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13140345313541 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13140345313495 and 13140345313504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13140345313549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570172656770 + 6570172656771.

It is an arithmetic number, because the mean of its divisors is an integer number (6570172656771).

Almost surely, 213140345313541 is an apocalyptic number.

It is an amenable number.

13140345313541 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140345313541 is an equidigital number, since it uses as much as digits as its factorization.

13140345313541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 38.

Adding to 13140345313541 its reverse (14531354304131), we get a palindrome (27671699617672).

The spelling of 13140345313541 in words is "thirteen trillion, one hundred forty billion, three hundred forty-five million, three hundred thirteen thousand, five hundred forty-one".