Base | Representation |
---|---|
bin | 1011111100110111111000… |
… | …1101111110010000010110 |
3 | 1201112012201122022012102001 |
4 | 2333031332031332100112 |
5 | 3210243041133104200 |
6 | 43540343215105514 |
7 | 2524235630523451 |
oct | 277157615762026 |
9 | 51465648265361 |
10 | 13140422550550 |
11 | 4206904a61369 |
12 | 1582850b1229a |
13 | 7441a0c56009 |
14 | 335ddd808498 |
15 | 17bc2c52376a |
hex | bf37e37e416 |
13140422550550 has 48 divisors (see below), whose sum is σ = 24478196076432. Its totient is φ = 5248214899200.
The previous prime is 13140422550539. The next prime is 13140422550583. The reversal of 13140422550550 is 5505522404131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 106803369 + ... + 106926331.
It is an arithmetic number, because the mean of its divisors is an integer number (509962418259).
Almost surely, 213140422550550 is an apocalyptic number.
13140422550550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13140422550550 is a deficient number, since it is larger than the sum of its proper divisors (11337773525882).
13140422550550 is a wasteful number, since it uses less digits than its factorization.
13140422550550 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 126193 (or 126188 counting only the distinct ones).
The product of its (nonzero) digits is 120000, while the sum is 37.
Adding to 13140422550550 its reverse (5505522404131), we get a palindrome (18645944954681).
The spelling of 13140422550550 in words is "thirteen trillion, one hundred forty billion, four hundred twenty-two million, five hundred fifty thousand, five hundred fifty".
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