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13140423122341 is a prime number
BaseRepresentation
bin1011111100110111111001…
…0000001001110110100101
31201112012201200101020202111
42333031332100021312211
53210243041304403331
643540343235241021
72524235635424464
oct277157620116645
951465650336674
1013140423122341
114206905311a19
121582851149171
137441a10c6358
14335ddd9169db
1517bc2c5d7db1
hexbf37e409da5

13140423122341 has 2 divisors, whose sum is σ = 13140423122342. Its totient is φ = 13140423122340.

The previous prime is 13140423122231. The next prime is 13140423122369. The reversal of 13140423122341 is 14322132404131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11846469096900 + 1293954025441 = 3441870^2 + 1137521^2 .

It is a cyclic number.

It is not a de Polignac number, because 13140423122341 - 231 = 13138275638693 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13140423122941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570211561170 + 6570211561171.

It is an arithmetic number, because the mean of its divisors is an integer number (6570211561171).

Almost surely, 213140423122341 is an apocalyptic number.

It is an amenable number.

13140423122341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140423122341 is an equidigital number, since it uses as much as digits as its factorization.

13140423122341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 13140423122341 its reverse (14322132404131), we get a palindrome (27462555526472).

The spelling of 13140423122341 in words is "thirteen trillion, one hundred forty billion, four hundred twenty-three million, one hundred twenty-two thousand, three hundred forty-one".