Base | Representation |
---|---|
bin | 11101111000001011111001… |
… | …010111010110110100111111 |
3 | 122020021010202111000222001121 |
4 | 131320023321113112310333 |
5 | 114210412214223302143 |
6 | 1143250204244451411 |
7 | 36451440566133325 |
oct | 3570137127266477 |
9 | 566233674028047 |
10 | 131404413103423 |
11 | 38962331544429 |
12 | 128a30800a9b67 |
13 | 58424c955c355 |
14 | 2464016933d15 |
15 | 102d1e4d7e7ed |
hex | 7782f95d6d3f |
131404413103423 has 2 divisors, whose sum is σ = 131404413103424. Its totient is φ = 131404413103422.
The previous prime is 131404413103277. The next prime is 131404413103427. The reversal of 131404413103423 is 324301314404131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131404413103423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131404413103427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65702206551711 + 65702206551712.
It is an arithmetic number, because the mean of its divisors is an integer number (65702206551712).
Almost surely, 2131404413103423 is an apocalyptic number.
131404413103423 is a deficient number, since it is larger than the sum of its proper divisors (1).
131404413103423 is an equidigital number, since it uses as much as digits as its factorization.
131404413103423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 131404413103423 its reverse (324301314404131), we get a palindrome (455705727507554).
The spelling of 131404413103423 in words is "one hundred thirty-one trillion, four hundred four billion, four hundred thirteen million, one hundred three thousand, four hundred twenty-three".
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