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1314045350197 is a prime number
BaseRepresentation
bin10011000111110011001…
…101001101000100110101
311122121210002011011120121
4103013303031031010311
5133012131102201242
62443355240131541
7163636161120256
oct23076315150465
94577702134517
101314045350197
11467313385728
12192807166bb1
1396bb5c24148
1447858aa8b2d
15242ac015667
hex131f334d135

1314045350197 has 2 divisors, whose sum is σ = 1314045350198. Its totient is φ = 1314045350196.

The previous prime is 1314045350179. The next prime is 1314045350221. The reversal of 1314045350197 is 7910535404131.

Together with previous prime (1314045350179) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1026004900561 + 288040449636 = 1012919^2 + 536694^2 .

It is an emirp because it is prime and its reverse (7910535404131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1314045350197 - 219 = 1314044825909 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1314085350197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657022675098 + 657022675099.

It is an arithmetic number, because the mean of its divisors is an integer number (657022675099).

Almost surely, 21314045350197 is an apocalyptic number.

It is an amenable number.

1314045350197 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314045350197 is an equidigital number, since it uses as much as digits as its factorization.

1314045350197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 226800, while the sum is 43.

The spelling of 1314045350197 in words is "one trillion, three hundred fourteen billion, forty-five million, three hundred fifty thousand, one hundred ninety-seven".