Base | Representation |
---|---|
bin | 1011111100111000011000… |
… | …0000000001101110111110 |
3 | 1201112020001201222102202012 |
4 | 2333032012000001232332 |
5 | 3210243323044100020 |
6 | 43540404201331222 |
7 | 2524242104344535 |
oct | 277160600015676 |
9 | 51466051872665 |
10 | 13140553112510 |
11 | 420697172750a |
12 | 1582888796b12 |
13 | 7441c200a505 |
14 | 336012cb331c |
15 | 17bc38c137c5 |
hex | bf386001bbe |
13140553112510 has 16 divisors (see below), whose sum is σ = 23656090466736. Its totient is φ = 5255533497408.
The previous prime is 13140553112429. The next prime is 13140553112581. The reversal of 13140553112510 is 1521135504131.
13140553112510 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×131405531125102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 85888199 + ... + 86041058.
It is an arithmetic number, because the mean of its divisors is an integer number (1478505654171).
Almost surely, 213140553112510 is an apocalyptic number.
13140553112510 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13140553112510 is a deficient number, since it is larger than the sum of its proper divisors (10515537354226).
13140553112510 is a wasteful number, since it uses less digits than its factorization.
13140553112510 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 171936907.
The product of its (nonzero) digits is 9000, while the sum is 32.
Adding to 13140553112510 its reverse (1521135504131), we get a palindrome (14661688616641).
The spelling of 13140553112510 in words is "thirteen trillion, one hundred forty billion, five hundred fifty-three million, one hundred twelve thousand, five hundred ten".
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