131405535143999 has 2 divisors, whose sum is σ = 131405535144000. Its totient is φ = 131405535143998.

The previous prime is 131405535143989. The next prime is 131405535144001. The reversal of 131405535143999 is 999341535504131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131405535143999 is a prime.

Together with 131405535144001, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131405535143989) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65702767571999 + 65702767572000.

It is an arithmetic number, because the mean of its divisors is an integer number (65702767572000).

Almost surely, 2^{131405535143999} is an apocalyptic number.

131405535143999 is a deficient number, since it is larger than the sum of its proper divisors (1).

131405535143999 is an equidigital number, since it uses as much as digits as its factorization.

131405535143999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 39366000, while the sum is 62.

The spelling of 131405535143999 in words is "one hundred thirty-one trillion, four hundred five billion, five hundred thirty-five million, one hundred forty-three thousand, nine hundred ninety-nine".