Base | Representation |
---|---|
bin | 10011000111110100000… |
… | …101000110110000010101 |
3 | 11122121211002201200022212 |
4 | 103013310011012300111 |
5 | 133012143330114443 |
6 | 2443400522203205 |
7 | 163636426512644 |
oct | 23076405066025 |
9 | 4577732650285 |
10 | 1314060004373 |
11 | 467320684616 |
12 | 192810053505 |
13 | 96bb8c8525c |
14 | 4785aa0135b |
15 | 242ad45c618 |
hex | 131f4146c15 |
1314060004373 has 2 divisors, whose sum is σ = 1314060004374. Its totient is φ = 1314060004372.
The previous prime is 1314060004363. The next prime is 1314060004391. The reversal of 1314060004373 is 3734000604131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1189587225124 + 124472779249 = 1090682^2 + 352807^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1314060004373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314060004303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657030002186 + 657030002187.
It is an arithmetic number, because the mean of its divisors is an integer number (657030002187).
Almost surely, 21314060004373 is an apocalyptic number.
It is an amenable number.
1314060004373 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314060004373 is an equidigital number, since it uses as much as digits as its factorization.
1314060004373 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 32.
The spelling of 1314060004373 in words is "one trillion, three hundred fourteen billion, sixty million, four thousand, three hundred seventy-three".
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