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1314061130022 = 23892460788633
BaseRepresentation
bin10011000111110100001…
…001011001100100100110
311122121211011211212102120
4103013310021121210212
5133012144122130042
62443401002250410
7163636442211504
oct23076411314446
94577734755376
101314061130022
11467321283303
121928104b6a06
1396bb928a714
144785ac15674
15242ad5d0dec
hex131f4259926

1314061130022 has 16 divisors (see below), whose sum is σ = 2657651724720. Its totient is φ = 433098799232.

The previous prime is 1314061129991. The next prime is 1314061130059. The reversal of 1314061130022 is 2200311604131.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 1314061129974 and 1314061130001.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1230393783 + ... + 1230394850.

It is an arithmetic number, because the mean of its divisors is an integer number (166103232795).

Almost surely, 21314061130022 is an apocalyptic number.

1314061130022 is an abundant number, since it is smaller than the sum of its proper divisors (1343590594698).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1314061130022 is a wasteful number, since it uses less digits than its factorization.

1314061130022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2460788727.

The product of its (nonzero) digits is 864, while the sum is 24.

Adding to 1314061130022 its reverse (2200311604131), we get a palindrome (3514372734153).

The spelling of 1314061130022 in words is "one trillion, three hundred fourteen billion, sixty-one million, one hundred thirty thousand, twenty-two".

Divisors: 1 2 3 6 89 178 267 534 2460788633 4921577266 7382365899 14764731798 219010188337 438020376674 657030565011 1314061130022