1314100450237 has 2 divisors, whose sum is σ = 1314100450238. Its totient is φ = 1314100450236.

The previous prime is 1314100450219. The next prime is 1314100450283. The reversal of 1314100450237 is 7320540014131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1245480552121 + 68619898116 = 1116011^2 + 261954^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1314100450237 is a prime.

It is a super-2 number, since 2×1314100450237² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1314100450199 and 1314100450208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1314100450207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657050225118 + 657050225119.

It is an arithmetic number, because the mean of its divisors is an integer number (657050225119).

Almost surely, 2^{1314100450237} is an apocalyptic number.

It is an amenable number.

1314100450237 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314100450237 is an equidigital number, since it uses as much as digits as its factorization.

1314100450237 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 31.

Adding to 1314100450237 its reverse (7320540014131), we get a palindrome (8634640464368).

The spelling of 1314100450237 in words is "one trillion, three hundred fourteen billion, one hundred million, four hundred fifty thousand, two hundred thirty-seven".