Base | Representation |
---|---|
bin | 10011000111110110011… |
… | …111011001001111101011 |
3 | 11122121220220211112200112 |
4 | 103013312133121033223 |
5 | 133012234203402113 |
6 | 2443404525124535 |
7 | 163640430346025 |
oct | 23076637311753 |
9 | 4577826745615 |
10 | 1314100450283 |
11 | 46734149a195 |
12 | 1928216b974b |
13 | 96bc4476a4a |
14 | 4786212d015 |
15 | 242b1c9b5a8 |
hex | 131f67d93eb |
1314100450283 has 2 divisors, whose sum is σ = 1314100450284. Its totient is φ = 1314100450282.
The previous prime is 1314100450237. The next prime is 1314100450309. The reversal of 1314100450283 is 3820540014131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1314100450283 - 26 = 1314100450219 is a prime.
It is not a weakly prime, because it can be changed into another prime (1314100450583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657050225141 + 657050225142.
It is an arithmetic number, because the mean of its divisors is an integer number (657050225142).
Almost surely, 21314100450283 is an apocalyptic number.
1314100450283 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314100450283 is an equidigital number, since it uses as much as digits as its factorization.
1314100450283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 32.
The spelling of 1314100450283 in words is "one trillion, three hundred fourteen billion, one hundred million, four hundred fifty thousand, two hundred eighty-three".
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