Base | Representation |
---|---|
bin | 1011111100111010001010… |
… | …0011101100010110001111 |
3 | 1201112021022010111211100111 |
4 | 2333032202203230112033 |
5 | 3210300313222133033 |
6 | 43540523514340451 |
7 | 2524260012622465 |
oct | 277164243542617 |
9 | 51467263454314 |
10 | 13141032224143 |
11 | 420709811713a |
12 | 15829a112a727 |
13 | 74426a35aa15 |
14 | 33605a78c835 |
15 | 17bc65d027cd |
hex | bf3a28ec58f |
13141032224143 has 2 divisors, whose sum is σ = 13141032224144. Its totient is φ = 13141032224142.
The previous prime is 13141032224093. The next prime is 13141032224171. The reversal of 13141032224143 is 34142223014131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13141032224143 - 217 = 13141032093071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13141032224443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570516112071 + 6570516112072.
It is an arithmetic number, because the mean of its divisors is an integer number (6570516112072).
Almost surely, 213141032224143 is an apocalyptic number.
13141032224143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141032224143 is an equidigital number, since it uses as much as digits as its factorization.
13141032224143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 13141032224143 its reverse (34142223014131), we get a palindrome (47283255238274).
The spelling of 13141032224143 in words is "thirteen trillion, one hundred forty-one billion, thirty-two million, two hundred twenty-four thousand, one hundred forty-three".
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