131411411505557 has 2 divisors, whose sum is σ = 131411411505558. Its totient is φ = 131411411505556.

The previous prime is 131411411505547. The next prime is 131411411505559. The reversal of 131411411505557 is 755505114114131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121111477664356 + 10299933841201 = 11005066^2 + 3209351^2 .

It is a cyclic number.

It is not a de Polignac number, because 131411411505557 - 2¹⁰ = 131411411504533 is a prime.

Together with 131411411505559, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131411411505559) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65705705752778 + 65705705752779.

It is an arithmetic number, because the mean of its divisors is an integer number (65705705752779).

Almost surely, 2^{131411411505557} is an apocalyptic number.

It is an amenable number.

131411411505557 is a deficient number, since it is larger than the sum of its proper divisors (1).

131411411505557 is an equidigital number, since it uses as much as digits as its factorization.

131411411505557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 210000, while the sum is 44.

Adding to 131411411505557 its reverse (755505114114131), we get a palindrome (886916525619688).

The spelling of 131411411505557 in words is "one hundred thirty-one trillion, four hundred eleven billion, four hundred eleven million, five hundred five thousand, five hundred fifty-seven".