Base | Representation |
---|---|
bin | 10011000111111001011… |
… | …110101110001010111111 |
3 | 11122122001102012200201021 |
4 | 103013321132232022333 |
5 | 133012340023334003 |
6 | 2443413520125011 |
7 | 163641606561121 |
oct | 23077136561277 |
9 | 4578042180637 |
10 | 1314150605503 |
11 | 46736783658a |
12 | 192836466767 |
13 | 96c019879a8 |
14 | 47868a67211 |
15 | 242b63a72bd |
hex | 131f97ae2bf |
1314150605503 has 2 divisors, whose sum is σ = 1314150605504. Its totient is φ = 1314150605502.
The previous prime is 1314150605491. The next prime is 1314150605519. The reversal of 1314150605503 is 3055060514131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1314150605503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314850605503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657075302751 + 657075302752.
It is an arithmetic number, because the mean of its divisors is an integer number (657075302752).
Almost surely, 21314150605503 is an apocalyptic number.
1314150605503 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314150605503 is an equidigital number, since it uses as much as digits as its factorization.
1314150605503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27000, while the sum is 34.
The spelling of 1314150605503 in words is "one trillion, three hundred fourteen billion, one hundred fifty million, six hundred five thousand, five hundred three".
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