Base | Representation |
---|---|
bin | 11101111000011010011100… |
… | …111011011101000101000111 |
3 | 122020022122002200212000100012 |
4 | 131320122130323131011013 |
5 | 114211141221242414221 |
6 | 1143301311153340435 |
7 | 36452533104645341 |
oct | 3570323473350507 |
9 | 566278080760305 |
10 | 131420042154311 |
11 | 38968a21756709 |
12 | 128a610226771b |
13 | 5843b1a505c61 |
14 | 2464a9a504291 |
15 | 102d80beee65b |
hex | 77869cedd147 |
131420042154311 has 2 divisors, whose sum is σ = 131420042154312. Its totient is φ = 131420042154310.
The previous prime is 131420042154287. The next prime is 131420042154383. The reversal of 131420042154311 is 113451240024131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131420042154311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131426042154311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65710021077155 + 65710021077156.
It is an arithmetic number, because the mean of its divisors is an integer number (65710021077156).
Almost surely, 2131420042154311 is an apocalyptic number.
131420042154311 is a deficient number, since it is larger than the sum of its proper divisors (1).
131420042154311 is an equidigital number, since it uses as much as digits as its factorization.
131420042154311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 131420042154311 its reverse (113451240024131), we get a palindrome (244871282178442).
The spelling of 131420042154311 in words is "one hundred thirty-one trillion, four hundred twenty billion, forty-two million, one hundred fifty-four thousand, three hundred eleven".
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