Base | Representation |
---|---|
bin | 1011111100111101110100… |
… | …0001100100011001000100 |
3 | 1201112100211111021020021011 |
4 | 2333033131001210121010 |
5 | 3210304320330300104 |
6 | 43541205114532004 |
7 | 2524323223335250 |
oct | 277173501443104 |
9 | 51470744236234 |
10 | 13142013134404 |
11 | 4207550891580 |
12 | 1583015737004 |
13 | 744395642bab |
14 | 336110b6b260 |
15 | 17bcc1eb2904 |
hex | bf3dd064644 |
13142013134404 has 96 divisors (see below), whose sum is σ = 29964571693056. Its totient is φ = 4894780423680.
The previous prime is 13142013134377. The next prime is 13142013134417. The reversal of 13142013134404 is 40443131024131.
13142013134404 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9933909 + ... + 11178844.
It is an arithmetic number, because the mean of its divisors is an integer number (312130955136).
Almost surely, 213142013134404 is an apocalyptic number.
13142013134404 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13142013134404 is an abundant number, since it is smaller than the sum of its proper divisors (16822558558652).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13142013134404 is a wasteful number, since it uses less digits than its factorization.
13142013134404 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21112865 (or 21112863 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 13142013134404 its reverse (40443131024131), we get a palindrome (53585144158535).
The spelling of 13142013134404 in words is "thirteen trillion, one hundred forty-two billion, thirteen million, one hundred thirty-four thousand, four hundred four".
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