Base | Representation |
---|---|
bin | 1011111100111101111011… |
… | …0111101111100111111000 |
3 | 1201112100220122120010110101 |
4 | 2333033132313233213320 |
5 | 3210304401243112100 |
6 | 43541212142525144 |
7 | 2524324050552106 |
oct | 277173667574770 |
9 | 51470818503411 |
10 | 13142044113400 |
11 | 4207567320554 |
12 | 1583023b967b4 |
13 | 74439bb9b667 |
14 | 336114d12c76 |
15 | 17bcc4a8186a |
hex | bf3dedef9f8 |
13142044113400 has 48 divisors (see below), whose sum is σ = 30624226252200. Its totient is φ = 5244951204480.
The previous prime is 13142044113397. The next prime is 13142044113409. The reversal of 13142044113400 is 431144024131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13142044113409) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 74076435 + ... + 74253634.
Almost surely, 213142044113400 is an apocalyptic number.
13142044113400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13142044113400 is an abundant number, since it is smaller than the sum of its proper divisors (17482182138800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13142044113400 is a wasteful number, since it uses less digits than its factorization.
13142044113400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 148330528 (or 148330519 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 13142044113400 its reverse (431144024131), we get a palindrome (13573188137531).
The spelling of 13142044113400 in words is "thirteen trillion, one hundred forty-two billion, forty-four million, one hundred thirteen thousand, four hundred".
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