13142125143100 has 36 divisors (see below), whose sum is σ = 28723580019400. Its totient is φ = 5219030986560.

The previous prime is 13142125143089. The next prime is 13142125143109. The reversal of 13142125143100 is 134152124131.

It is a super-3 number, since 3×13142125143100³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13142125143109) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 472724415 + ... + 472752214.

Almost surely, 2^{13142125143100} is an apocalyptic number.

13142125143100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13142125143100 is an abundant number, since it is smaller than the sum of its proper divisors (15581454876300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13142125143100 is a wasteful number, since it uses less digits than its factorization.

13142125143100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 945476782 (or 945476775 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 13142125143100 its reverse (134152124131), we get a palindrome (13276277267231).

The spelling of 13142125143100 in words is "thirteen trillion, one hundred forty-two billion, one hundred twenty-five million, one hundred forty-three thousand, one hundred".