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131421412142400 = 26352277317311807
BaseRepresentation
bin11101111000011011101110…
…100101100010110101000000
3122020022202122011201121200210
4131320123232211202311000
5114211202023002024100
61143302055133114120
736452612051442612
oct3570335645426500
9566282564647623
10131421412142400
1138969565006a76
12128a6425028940
135843ca82a71b3
142464b8a442db2
15102d88c416c50
hex7786ee962d40

131421412142400 has 336 divisors, whose sum is σ = 434094792155136. Its totient is φ = 34808924282880.

The previous prime is 131421412142389. The next prime is 131421412142401. The reversal of 131421412142400 is 4241214124131.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131421412142401) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 421327297 + ... + 421639103.

It is an arithmetic number, because the mean of its divisors is an integer number (1291948786176).

Almost surely, 2131421412142400 is an apocalyptic number.

131421412142400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131421412142400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (217047396077568).

131421412142400 is an abundant number, since it is smaller than the sum of its proper divisors (302673380012736).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131421412142400 is a wasteful number, since it uses less digits than its factorization.

131421412142400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 312426 (or 312411 counting only the distinct ones).

The product of its (nonzero) digits is 6144, while the sum is 30.

Adding to 131421412142400 its reverse (4241214124131), we get a palindrome (135662626266531).

The spelling of 131421412142400 in words is "one hundred thirty-one trillion, four hundred twenty-one billion, four hundred twelve million, one hundred forty-two thousand, four hundred".