13142220431 has 2 divisors, whose sum is σ = 13142220432. Its totient is φ = 13142220430.

The previous prime is 13142220391. The next prime is 13142220433. The reversal of 13142220431 is 13402224131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13142220431 is a prime.

It is a super-2 number, since 2×13142220431² (a number of 21 digits) contains 22 as substring.

Together with 13142220433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13142220397 and 13142220406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13142220433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571110215 + 6571110216.

It is an arithmetic number, because the mean of its divisors is an integer number (6571110216).

Almost surely, 2^13142220431 is an apocalyptic number.

13142220431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13142220431 is an equidigital number, since it uses as much as digits as its factorization.

13142220431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13142220431 its reverse (13402224131), we get a palindrome (26544444562).

The spelling of 13142220431 in words is "thirteen billion, one hundred forty-two million, two hundred twenty thousand, four hundred thirty-one".