Base | Representation |
---|---|
bin | 11000011110101011… |
… | …01011101010101101 |
3 | 1020220220110011120021 |
4 | 30033111223222231 |
5 | 203403403302023 |
6 | 10012031522141 |
7 | 643451142133 |
oct | 141725535255 |
9 | 36826404507 |
10 | 13142244013 |
11 | 56344aa498 |
12 | 2669389351 |
13 | 13159b6562 |
14 | 8c95d5753 |
15 | 51db9d35d |
hex | 30f56baad |
13142244013 has 2 divisors, whose sum is σ = 13142244014. Its totient is φ = 13142244012.
The previous prime is 13142243993. The next prime is 13142244061. The reversal of 13142244013 is 31044224131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12091641444 + 1050602569 = 109962^2 + 32413^2 .
It is an emirp because it is prime and its reverse (31044224131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13142244013 - 25 = 13142243981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13142244113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571122006 + 6571122007.
It is an arithmetic number, because the mean of its divisors is an integer number (6571122007).
Almost surely, 213142244013 is an apocalyptic number.
It is an amenable number.
13142244013 is a deficient number, since it is larger than the sum of its proper divisors (1).
13142244013 is an equidigital number, since it uses as much as digits as its factorization.
13142244013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13142244013 its reverse (31044224131), we get a palindrome (44186468144).
The spelling of 13142244013 in words is "thirteen billion, one hundred forty-two million, two hundred forty-four thousand, thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •