Base | Representation |
---|---|
bin | 11101111000011101100001… |
… | …101011100100100000111101 |
3 | 122020022221121202011112022111 |
4 | 131320131201223210200331 |
5 | 114211220001313231023 |
6 | 1143303014512214021 |
7 | 36453010646355514 |
oct | 3570354153444075 |
9 | 566287552145274 |
10 | 131423343102013 |
11 | 3896a365a88566 |
12 | 128a688383a311 |
13 | 584422535a751 |
14 | 2464cd0a8967b |
15 | 102d951bdd00d |
hex | 778761ae483d |
131423343102013 has 2 divisors, whose sum is σ = 131423343102014. Its totient is φ = 131423343102012.
The previous prime is 131423343102011. The next prime is 131423343102031. The reversal of 131423343102013 is 310201343324131.
Together with next prime (131423343102031) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 129840509878564 + 1582833223449 = 11394758^2 + 1258107^2 .
It is a cyclic number.
It is not a de Polignac number, because 131423343102013 - 21 = 131423343102011 is a prime.
It is a super-2 number, since 2×1314233431020132 (a number of 29 digits) contains 22 as substring.
Together with 131423343102011, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131423343102011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711671551006 + 65711671551007.
It is an arithmetic number, because the mean of its divisors is an integer number (65711671551007).
Almost surely, 2131423343102013 is an apocalyptic number.
It is an amenable number.
131423343102013 is a deficient number, since it is larger than the sum of its proper divisors (1).
131423343102013 is an equidigital number, since it uses as much as digits as its factorization.
131423343102013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 131423343102013 its reverse (310201343324131), we get a palindrome (441624686426144).
The spelling of 131423343102013 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, three hundred forty-three million, one hundred two thousand, thirteen".
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