13142341439453 has 2 divisors, whose sum is σ = 13142341439454. Its totient is φ = 13142341439452.

The previous prime is 13142341439429. The next prime is 13142341439537. The reversal of 13142341439453 is 35493414324131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12712376655364 + 429964784089 = 3565442^2 + 655717^2 .

It is a cyclic number.

It is not a de Polignac number, because 13142341439453 - 2⁸ = 13142341439197 is a prime.

It is a super-2 number, since 2×13142341439453² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13142341439398 and 13142341439407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13142341439053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571170719726 + 6571170719727.

It is an arithmetic number, because the mean of its divisors is an integer number (6571170719727).

Almost surely, 2^{13142341439453} is an apocalyptic number.

It is an amenable number.

13142341439453 is a deficient number, since it is larger than the sum of its proper divisors (1).

13142341439453 is an equidigital number, since it uses as much as digits as its factorization.

13142341439453 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1866240, while the sum is 47.

The spelling of 13142341439453 in words is "thirteen trillion, one hundred forty-two billion, three hundred forty-one million, four hundred thirty-nine thousand, four hundred fifty-three".