13142341441501 has 4 divisors (see below), whose sum is σ = 13238270941212. Its totient is φ = 13046411941792.

The previous prime is 13142341441403. The next prime is 13142341441517. The reversal of 13142341441501 is 10514414324131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4481392624900 + 8660948816601 = 2116930^2 + 2942949^2 .

It is a cyclic number.

It is not a de Polignac number, because 13142341441501 - 2¹¹ = 13142341439453 is a prime.

It is a super-2 number, since 2×13142341441501² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13142341441601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47964749650 + ... + 47964749923.

It is an arithmetic number, because the mean of its divisors is an integer number (3309567735303).

Almost surely, 2^{13142341441501} is an apocalyptic number.

It is an amenable number.

13142341441501 is a deficient number, since it is larger than the sum of its proper divisors (95929499711).

13142341441501 is an equidigital number, since it uses as much as digits as its factorization.

13142341441501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 95929499710.

The product of its (nonzero) digits is 23040, while the sum is 34.

Adding to 13142341441501 its reverse (10514414324131), we get a palindrome (23656755765632).

The spelling of 13142341441501 in words is "thirteen trillion, one hundred forty-two billion, three hundred forty-one million, four hundred forty-one thousand, five hundred one".