Base | Representation |
---|---|
bin | 11000011110110001… |
… | …01100100010010000 |
3 | 1020220221221022020001 |
4 | 30033120230202100 |
5 | 203404104042000 |
6 | 10012100455344 |
7 | 643460642245 |
oct | 141730544220 |
9 | 36827838201 |
10 | 13143034000 |
11 | 5634999a78 |
12 | 26696aa554 |
13 | 1315c01cc5 |
14 | 8c975d5cc |
15 | 51dca746a |
hex | 30f62c890 |
13143034000 has 80 divisors (see below), whose sum is σ = 31825503216. Its totient is φ = 5249664000.
The previous prime is 13143033991. The next prime is 13143034013. The reversal of 13143034000 is 43034131.
It can be written as a sum of positive squares in 8 ways, for example, as 1716279184 + 11426754816 = 41428^2 + 106896^2 .
It is a tau number, because it is divible by the number of its divisors (80).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1509660 + ... + 1518340.
Almost surely, 213143034000 is an apocalyptic number.
13143034000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13143034000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15912751608).
13143034000 is an abundant number, since it is smaller than the sum of its proper divisors (18682469216).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13143034000 is an equidigital number, since it uses as much as digits as its factorization.
13143034000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9461 (or 9445 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 13143034000 its reverse (43034131), we get a palindrome (13186068131).
The spelling of 13143034000 in words is "thirteen billion, one hundred forty-three million, thirty-four thousand".
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