Base | Representation |
---|---|
bin | 11000011110110001… |
… | …01111000011001111 |
3 | 1020220221221211100122 |
4 | 30033120233003033 |
5 | 203404104404203 |
6 | 10012101015155 |
7 | 643461014264 |
oct | 141730570317 |
9 | 36827854318 |
10 | 13143044303 |
11 | 56349a6794 |
12 | 26696b44bb |
13 | 1315c068bc |
14 | 8c976326b |
15 | 51dcaa538 |
hex | 30f62f0cf |
13143044303 has 2 divisors, whose sum is σ = 13143044304. Its totient is φ = 13143044302.
The previous prime is 13143044279. The next prime is 13143044311. The reversal of 13143044303 is 30344034131.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (30344034131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13143044303 is a prime.
It is a super-2 number, since 2×131430443032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13143046303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571522151 + 6571522152.
It is an arithmetic number, because the mean of its divisors is an integer number (6571522152).
Almost surely, 213143044303 is an apocalyptic number.
13143044303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13143044303 is an equidigital number, since it uses as much as digits as its factorization.
13143044303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 13143044303 its reverse (30344034131), we get a palindrome (43487078434).
The spelling of 13143044303 in words is "thirteen billion, one hundred forty-three million, forty-four thousand, three hundred three".
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