Base | Representation |
---|---|
bin | 1011111101000001111100… |
… | …1100001001010010000111 |
3 | 1201112110200212001120101112 |
4 | 2333100133030021102013 |
5 | 3210314104020000312 |
6 | 43541511211315235 |
7 | 2524362562635404 |
oct | 277203714112207 |
9 | 51473625046345 |
10 | 13143123203207 |
11 | 4207a70453708 |
12 | 158328544bb1b |
13 | 74451160a83a |
14 | 3361b836b2ab |
15 | 17bd39686d22 |
hex | bf41f309487 |
13143123203207 has 2 divisors, whose sum is σ = 13143123203208. Its totient is φ = 13143123203206.
The previous prime is 13143123203143. The next prime is 13143123203323. The reversal of 13143123203207 is 70230232134131.
13143123203207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13143123203207 - 26 = 13143123203143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13143123203107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571561601603 + 6571561601604.
It is an arithmetic number, because the mean of its divisors is an integer number (6571561601604).
Almost surely, 213143123203207 is an apocalyptic number.
13143123203207 is a deficient number, since it is larger than the sum of its proper divisors (1).
13143123203207 is an equidigital number, since it uses as much as digits as its factorization.
13143123203207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 32.
Adding to 13143123203207 its reverse (70230232134131), we get a palindrome (83373355337338).
The spelling of 13143123203207 in words is "thirteen trillion, one hundred forty-three billion, one hundred twenty-three million, two hundred three thousand, two hundred seven".
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