13143320120 has 64 divisors (see below), whose sum is σ = 33808734720. Its totient is φ = 4504731264.

The previous prime is 13143320089. The next prime is 13143320131. The reversal of 13143320120 is 2102334131.

13143320120 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 13143320092 and 13143320101.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1058669 + ... + 1071011.

It is an arithmetic number, because the mean of its divisors is an integer number (528261480).

Almost surely, 2^13143320120 is an apocalyptic number.

13143320120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13143320120 is an abundant number, since it is smaller than the sum of its proper divisors (20665414600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13143320120 is a wasteful number, since it uses less digits than its factorization.

13143320120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16164 (or 16160 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13143320120 its reverse (2102334131), we get a palindrome (15245654251).

The spelling of 13143320120 in words is "thirteen billion, one hundred forty-three million, three hundred twenty thousand, one hundred twenty".