Base | Representation |
---|---|
bin | 1011111101000010101111… |
… | …0000010001101001000111 |
3 | 1201112111020112201012220110 |
4 | 2333100223300101221013 |
5 | 3210320022001014343 |
6 | 43541544141404103 |
7 | 2524401032455026 |
oct | 277205360215107 |
9 | 51474215635813 |
10 | 13143334001223 |
11 | 4208069441348 |
12 | 1583323b69633 |
13 | 7445461a59aa |
14 | 3361d83608bd |
15 | 17bd4ce25833 |
hex | bf42bc11a47 |
13143334001223 has 64 divisors (see below), whose sum is σ = 19732520079360. Its totient is φ = 7741286961408.
The previous prime is 13143334001201. The next prime is 13143334001243. The reversal of 13143334001223 is 32210043334131.
13143334001223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13143334001223 - 25 = 13143334001191 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13143334001243) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 30622915 + ... + 31049147.
It is an arithmetic number, because the mean of its divisors is an integer number (308320626240).
Almost surely, 213143334001223 is an apocalyptic number.
13143334001223 is a deficient number, since it is larger than the sum of its proper divisors (6589186078137).
13143334001223 is a wasteful number, since it uses less digits than its factorization.
13143334001223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 426868.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 13143334001223 its reverse (32210043334131), we get a palindrome (45353377335354).
The spelling of 13143334001223 in words is "thirteen trillion, one hundred forty-three billion, three hundred thirty-four million, one thousand, two hundred twenty-three".
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