Base | Representation |
---|---|
bin | 111101001101000001… |
… | …0101101010011111111 |
3 | 110120020211011112020121 |
4 | 1322122002231103333 |
5 | 4123133423420111 |
6 | 140214002155411 |
7 | 12332020431334 |
oct | 1723202552377 |
9 | 416224145217 |
10 | 131433420031 |
11 | 50816814891 |
12 | 21580952b67 |
13 | c517b54b74 |
14 | 650b9da98b |
15 | 3643b0a871 |
hex | 1e9a0ad4ff |
131433420031 has 2 divisors, whose sum is σ = 131433420032. Its totient is φ = 131433420030.
The previous prime is 131433419977. The next prime is 131433420073. The reversal of 131433420031 is 130024334131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131433420031 - 219 = 131432895743 is a prime.
It is a super-2 number, since 2×1314334200312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131433419978 and 131433420005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131433423031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65716710015 + 65716710016.
It is an arithmetic number, because the mean of its divisors is an integer number (65716710016).
Almost surely, 2131433420031 is an apocalyptic number.
131433420031 is a deficient number, since it is larger than the sum of its proper divisors (1).
131433420031 is an equidigital number, since it uses as much as digits as its factorization.
131433420031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 131433420031 its reverse (130024334131), we get a palindrome (261457754162).
The spelling of 131433420031 in words is "one hundred thirty-one billion, four hundred thirty-three million, four hundred twenty thousand, thirty-one".
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