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13143413450327 is a prime number
BaseRepresentation
bin1011111101000011000001…
…1111010110011001010111
31201112111110002012122120212
42333100300133112121113
53210320202320402302
643542000100320035
72524403015665046
oct277206037263127
951474402178525
1013143413450327
1142080aa276666
1215833466a301b
137445597a23b4
14336204b2255d
1517bd54dbb052
hexbf4307d6657

13143413450327 has 2 divisors, whose sum is σ = 13143413450328. Its totient is φ = 13143413450326.

The previous prime is 13143413450309. The next prime is 13143413450329. The reversal of 13143413450327 is 72305431434131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13143413450327 - 28 = 13143413450071 is a prime.

Together with 13143413450329, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13143413450329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571706725163 + 6571706725164.

It is an arithmetic number, because the mean of its divisors is an integer number (6571706725164).

Almost surely, 213143413450327 is an apocalyptic number.

13143413450327 is a deficient number, since it is larger than the sum of its proper divisors (1).

13143413450327 is an equidigital number, since it uses as much as digits as its factorization.

13143413450327 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 362880, while the sum is 41.

Adding to 13143413450327 its reverse (72305431434131), we get a palindrome (85448844884458).

The spelling of 13143413450327 in words is "thirteen trillion, one hundred forty-three billion, four hundred thirteen million, four hundred fifty thousand, three hundred twenty-seven".