Base | Representation |
---|---|
bin | 1011111101000011000011… |
… | …1000010101011111111101 |
3 | 1201112111110112112102101201 |
4 | 2333100300320111133331 |
5 | 3210320211010002003 |
6 | 43542000452535501 |
7 | 2524403125445044 |
oct | 277206070253775 |
9 | 51474415472351 |
10 | 13143420000253 |
11 | 4208102a3a724 |
12 | 1583348921591 |
13 | 74455ac567aa |
14 | 33620594955b |
15 | 17bd55761b1d |
hex | bf430e157fd |
13143420000253 has 2 divisors, whose sum is σ = 13143420000254. Its totient is φ = 13143420000252.
The previous prime is 13143420000181. The next prime is 13143420000311. The reversal of 13143420000253 is 35200002434131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11466804195289 + 1676615804964 = 3386267^2 + 1294842^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13143420000253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13143420003253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571710000126 + 6571710000127.
It is an arithmetic number, because the mean of its divisors is an integer number (6571710000127).
Almost surely, 213143420000253 is an apocalyptic number.
It is an amenable number.
13143420000253 is a deficient number, since it is larger than the sum of its proper divisors (1).
13143420000253 is an equidigital number, since it uses as much as digits as its factorization.
13143420000253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 13143420000253 its reverse (35200002434131), we get a palindrome (48343422434384).
The spelling of 13143420000253 in words is "thirteen trillion, one hundred forty-three billion, four hundred twenty million, two hundred fifty-three", and thus it is an aban number.
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