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1314400106497 is a prime number
BaseRepresentation
bin10011001000001000010…
…110011111100000000001
311122122200210200122201211
4103020020112133200001
5133013342411401442
62443454351530121
7163651026364222
oct23101026374001
94578623618654
101314400106497
11467485659355
121928a5b29941
1396c4158420a
144788dc53249
15242cd23d617
hex1320859f801

1314400106497 has 2 divisors, whose sum is σ = 1314400106498. Its totient is φ = 1314400106496.

The previous prime is 1314400106447. The next prime is 1314400106519. The reversal of 1314400106497 is 7946010044131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 861126464961 + 453273641536 = 927969^2 + 673256^2 .

It is a cyclic number.

It is not a de Polignac number, because 1314400106497 - 227 = 1314265888769 is a prime.

It is a super-2 number, since 2×13144001064972 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1314400106447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657200053248 + 657200053249.

It is an arithmetic number, because the mean of its divisors is an integer number (657200053249).

Almost surely, 21314400106497 is an apocalyptic number.

It is an amenable number.

1314400106497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314400106497 is an equidigital number, since it uses as much as digits as its factorization.

1314400106497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72576, while the sum is 40.

The spelling of 1314400106497 in words is "one trillion, three hundred fourteen billion, four hundred million, one hundred six thousand, four hundred ninety-seven".