Base | Representation |
---|---|
bin | 10011001000001000010… |
… | …110011111100000010111 |
3 | 11122122200210200122202122 |
4 | 103020020112133200113 |
5 | 133013342411402034 |
6 | 2443454351530155 |
7 | 163651026364253 |
oct | 23101026374027 |
9 | 4578623618678 |
10 | 1314400106519 |
11 | 467485659375 |
12 | 1928a5b2995b |
13 | 96c41584226 |
14 | 4788dc53263 |
15 | 242cd23d62e |
hex | 1320859f817 |
1314400106519 has 2 divisors, whose sum is σ = 1314400106520. Its totient is φ = 1314400106518.
The previous prime is 1314400106497. The next prime is 1314400106527. The reversal of 1314400106519 is 9156010044131.
It is a strong prime.
It is an emirp because it is prime and its reverse (9156010044131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1314400106519 - 228 = 1314131671063 is a prime.
It is a super-2 number, since 2×13144001065192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314400106419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657200053259 + 657200053260.
It is an arithmetic number, because the mean of its divisors is an integer number (657200053260).
Almost surely, 21314400106519 is an apocalyptic number.
1314400106519 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314400106519 is an equidigital number, since it uses as much as digits as its factorization.
1314400106519 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 35.
The spelling of 1314400106519 in words is "one trillion, three hundred fourteen billion, four hundred million, one hundred six thousand, five hundred nineteen".
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