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131440656233 is a prime number
BaseRepresentation
bin111101001101001111…
…0010011111101101001
3110120021022210011110002
41322122132103331221
54123142301444413
6140214421232345
712332136100205
oct1723236237551
9416238704402
10131440656233
115081a907517
12215832626b5
13c5194b9743
14650c961b05
153644589958
hex1e9a793f69

131440656233 has 2 divisors, whose sum is σ = 131440656234. Its totient is φ = 131440656232.

The previous prime is 131440656199. The next prime is 131440656271. The reversal of 131440656233 is 332656044131.

It is an a-pointer prime, because the next prime (131440656271) can be obtained adding 131440656233 to its sum of digits (38).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111939092329 + 19501563904 = 334573^2 + 139648^2 .

It is a cyclic number.

It is not a de Polignac number, because 131440656233 - 26 = 131440656169 is a prime.

It is a super-2 number, since 2×1314406562332 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131440656283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65720328116 + 65720328117.

It is an arithmetic number, because the mean of its divisors is an integer number (65720328117).

Almost surely, 2131440656233 is an apocalyptic number.

It is an amenable number.

131440656233 is a deficient number, since it is larger than the sum of its proper divisors (1).

131440656233 is an equidigital number, since it uses as much as digits as its factorization.

131440656233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 38.

The spelling of 131440656233 in words is "one hundred thirty-one billion, four hundred forty million, six hundred fifty-six thousand, two hundred thirty-three".