Base | Representation |
---|---|
bin | 10011001000001001110… |
… | …000001101100101000011 |
3 | 11122122202102221120111102 |
4 | 103020021300031211003 |
5 | 133013414422013201 |
6 | 2443500552005015 |
7 | 163651433322314 |
oct | 23101160154503 |
9 | 4578672846442 |
10 | 1314423626051 |
11 | 4674979629a8 |
12 | 1928b199076b |
13 | 96c463ca603 |
14 | 4789301660b |
15 | 242d033726b |
hex | 13209c0d943 |
1314423626051 has 2 divisors, whose sum is σ = 1314423626052. Its totient is φ = 1314423626050.
The previous prime is 1314423626039. The next prime is 1314423626053. The reversal of 1314423626051 is 1506263244131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1314423626051 - 222 = 1314419431747 is a prime.
It is a Sophie Germain prime.
Together with 1314423626053, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1314423625996 and 1314423626014.
It is not a weakly prime, because it can be changed into another prime (1314423626053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657211813025 + 657211813026.
It is an arithmetic number, because the mean of its divisors is an integer number (657211813026).
Almost surely, 21314423626051 is an apocalyptic number.
1314423626051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314423626051 is an equidigital number, since it uses as much as digits as its factorization.
1314423626051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 38.
The spelling of 1314423626051 in words is "one trillion, three hundred fourteen billion, four hundred twenty-three million, six hundred twenty-six thousand, fifty-one".
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