Base | Representation |
---|---|
bin | 10011001000001010001… |
… | …000100101001000101111 |
3 | 11122122202212222010010002 |
4 | 103020022020211020233 |
5 | 133013423040421444 |
6 | 2443501340534515 |
7 | 163651541526134 |
oct | 23101210451057 |
9 | 4578685863102 |
10 | 1314430013999 |
11 | 4674a05262a3 |
12 | 1928b3b5143b |
13 | 96c4782606b |
14 | 47893bda58b |
15 | 242d0b99d4e |
hex | 1320a22522f |
1314430013999 has 2 divisors, whose sum is σ = 1314430014000. Its totient is φ = 1314430013998.
The previous prime is 1314430013993. The next prime is 1314430014017. The reversal of 1314430013999 is 9993100344131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1314430013999 is a prime.
It is a super-2 number, since 2×13144300139992 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314430013993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657215006999 + 657215007000.
It is an arithmetic number, because the mean of its divisors is an integer number (657215007000).
Almost surely, 21314430013999 is an apocalyptic number.
1314430013999 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314430013999 is an equidigital number, since it uses as much as digits as its factorization.
1314430013999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 314928, while the sum is 47.
The spelling of 1314430013999 in words is "one trillion, three hundred fourteen billion, four hundred thirty million, thirteen thousand, nine hundred ninety-nine".
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