Base | Representation |
---|---|
bin | 100111001011000… |
… | …1100010011101111 |
3 | 10101121100111021221 |
4 | 1032112030103233 |
5 | 10142444043211 |
6 | 334233004211 |
7 | 44400362563 |
oct | 11626142357 |
9 | 3347314257 |
10 | 1314440431 |
11 | 614a70607 |
12 | 308253667 |
13 | 17c422a05 |
14 | c67dd6a3 |
15 | 7a5e3c71 |
hex | 4e58c4ef |
1314440431 has 2 divisors, whose sum is σ = 1314440432. Its totient is φ = 1314440430.
The previous prime is 1314440419. The next prime is 1314440461. The reversal of 1314440431 is 1340444131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1314440431 - 215 = 1314407663 is a prime.
It is a super-2 number, since 2×13144404312 = 3455507293294931522, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1314440396 and 1314440405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314440411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657220215 + 657220216.
It is an arithmetic number, because the mean of its divisors is an integer number (657220216).
Almost surely, 21314440431 is an apocalyptic number.
1314440431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314440431 is an equidigital number, since it uses as much as digits as its factorization.
1314440431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
The square root of 1314440431 is about 36255.2124666233. The cubic root of 1314440431 is about 1095.4190846661.
Adding to 1314440431 its reverse (1340444131), we get a palindrome (2654884562).
The spelling of 1314440431 in words is "one billion, three hundred fourteen million, four hundred forty thousand, four hundred thirty-one".
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