Base | Representation |
---|---|
bin | 10011001000001010111… |
… | …110011010000010101111 |
3 | 11122122210212111222212010 |
4 | 103020022332122002233 |
5 | 133013440143434320 |
6 | 2443503003212303 |
7 | 163652102465136 |
oct | 23101276320257 |
9 | 4578725458763 |
10 | 1314444124335 |
11 | 4674a8493631 |
12 | 1928b8817093 |
13 | 96c4a726784 |
14 | 47895a3091d |
15 | 242d2035ae0 |
hex | 1320af9a0af |
1314444124335 has 64 divisors (see below), whose sum is σ = 2143831196160. Its totient is φ = 687581706240.
The previous prime is 1314444124327. The next prime is 1314444124381. The reversal of 1314444124335 is 5334214444131.
It is a happy number.
It is not a de Polignac number, because 1314444124335 - 23 = 1314444124327 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1314444124293 and 1314444124302.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 148235572 + ... + 148244438.
It is an arithmetic number, because the mean of its divisors is an integer number (33497362440).
Almost surely, 21314444124335 is an apocalyptic number.
1314444124335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1314444124335 is a deficient number, since it is larger than the sum of its proper divisors (829387071825).
1314444124335 is a wasteful number, since it uses less digits than its factorization.
1314444124335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9688.
The product of its digits is 276480, while the sum is 39.
Adding to 1314444124335 its reverse (5334214444131), we get a palindrome (6648658568466).
The spelling of 1314444124335 in words is "one trillion, three hundred fourteen billion, four hundred forty-four million, one hundred twenty-four thousand, three hundred thirty-five".
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