Base | Representation |
---|---|
bin | 1011111101000110111001… |
… | …1001010000011001110110 |
3 | 1201112121010110111111012112 |
4 | 2333101232121100121312 |
5 | 3210324314210242220 |
6 | 43542251121051022 |
7 | 2524440526602143 |
oct | 277215631203166 |
9 | 51477113444175 |
10 | 13144452040310 |
11 | 4208592557698 |
12 | 1583596486a72 |
13 | 744693a01396 |
14 | 3362a2a373ca |
15 | 17bdb61715c5 |
hex | bf46e650676 |
13144452040310 has 16 divisors (see below), whose sum is σ = 24210246549456. Its totient is φ = 5135506843488.
The previous prime is 13144452040289. The next prime is 13144452040319. The reversal of 13144452040310 is 1304025444131.
It is a super-2 number, since 2×131444520403102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13144452040319) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15284246129 + ... + 15284246988.
It is an arithmetic number, because the mean of its divisors is an integer number (1513140409341).
Almost surely, 213144452040310 is an apocalyptic number.
13144452040310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13144452040310 is a deficient number, since it is larger than the sum of its proper divisors (11065794509146).
13144452040310 is a wasteful number, since it uses less digits than its factorization.
13144452040310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30568493167.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 13144452040310 its reverse (1304025444131), we get a palindrome (14448477484441).
The spelling of 13144452040310 in words is "thirteen trillion, one hundred forty-four billion, four hundred fifty-two million, forty thousand, three hundred ten".
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