Base | Representation |
---|---|
bin | 10011001000001111101… |
… | …100111100101001001000 |
3 | 11122200000101202022122020 |
4 | 103020033230330221020 |
5 | 133014120444333134 |
6 | 2443514515124440 |
7 | 163654054553256 |
oct | 23101754745110 |
9 | 4580011668566 |
10 | 1314523433544 |
11 | 467539232832 |
12 | 19291b2a3720 |
13 | 96c60ca45b9 |
14 | 478a23975d6 |
15 | 242d8e9eb49 |
hex | 1320fb3ca48 |
1314523433544 has 32 divisors (see below), whose sum is σ = 3362734367520. Its totient is φ = 427984373376.
The previous prime is 1314523433543. The next prime is 1314523433557. The reversal of 1314523433544 is 4453343254131.
It is a junction number, because it is equal to n+sod(n) for n = 1314523433496 and 1314523433505.
It is not an unprimeable number, because it can be changed into a prime (1314523433543) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 636880477 + ... + 636882540.
It is an arithmetic number, because the mean of its divisors is an integer number (105085448985).
Almost surely, 21314523433544 is an apocalyptic number.
It is an amenable number.
1314523433544 is an abundant number, since it is smaller than the sum of its proper divisors (2048210933976).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1314523433544 is a wasteful number, since it uses less digits than its factorization.
1314523433544 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1273763069 (or 1273763065 counting only the distinct ones).
The product of its digits is 1036800, while the sum is 42.
Adding to 1314523433544 its reverse (4453343254131), we get a palindrome (5767866687675).
The spelling of 1314523433544 in words is "one trillion, three hundred fourteen billion, five hundred twenty-three million, four hundred thirty-three thousand, five hundred forty-four".
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